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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 7

Answers (1)

Answer:

                \frac{1}{\sqrt3}

Hint:

You must know the value of inverse trigonometric function.

Given:

\tan^{-1}\left (\frac{1}{\sqrt3} \right )+\cot^{-1}x=\frac{\pi}{2}

Solution:

                \tan^{-1}\left (\frac{1}{\sqrt3} \right )+\cot^{-1}x=\frac{\pi}{2}

\Rightarrow         \tan^{-1}\left (\frac{1}{\sqrt3} \right )=\frac{\pi}{2}-\cot^{-1}x

\Rightarrow         \tan^{-1}\left (\frac{1}{\sqrt3} \right )=\tan^{-1}x

\Rightarrow         x=\frac{1}{\sqrt3}

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