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Name: Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 7
Uploaded: Sun, 2021-07-25 09:21
Description: Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 7

#Inverse Trigonometric Functions
#R.D. Sharma
#School
#RD Sharma Vol. 1 Class 12
#Maths
#CBSE 12 Class

#1.3
#3.1
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#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 7

Answers (1)

Answer:

$\frac{1}{\sqrt3}$

Hint:

You must know the value of inverse trigonometric function.

Given:

$\tan^{-1}\left (\frac{1}{\sqrt3} \right )+\cot^{-1}x=\frac{\pi}{2}$

Solution:

$\tan^{-1}\left (\frac{1}{\sqrt3} \right )+\cot^{-1}x=\frac{\pi}{2}$

$\Rightarrow$ $\tan^{-1}\left (\frac{1}{\sqrt3} \right )=\frac{\pi}{2}-\cot^{-1}x$

$\Rightarrow$ $\tan^{-1}\left (\frac{1}{\sqrt3} \right )=\tan^{-1}x$

$\Rightarrow$ $x=\frac{1}{\sqrt3}$

Posted by

infoexpert27

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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 7

Answers (1)

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