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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 46 Maths Textbook Solution.

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Answer: \frac{-\pi}{10}

Hint: Let’s start with cos function and solve \sin ^{-1} function.

Given: \sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)

Solution:

\sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)=\sin ^{-1}\left\{\cos \left(6 \pi+\frac{3 \pi}{5}\right)\right\}

                                  =\sin ^{-1}\left\{\sin \left(\frac{\pi}{2}-\frac{3 \pi}{5}\right)\right\}

                                   =\frac{\pi}{2}-\frac{3 \pi}{5}

                                   =\frac{-\pi}{10}

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