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Name: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 46 Maths Textbook Solution.
Uploaded: Thu, 2021-08-05 17:54
Description: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 46 Maths Textbook Solution.

#Inverse Trigonometric Functions
#Maths
#R.D. Sharma
#RD Sharma Vol. 1 Class 12
#School
#CBSE 12 Class

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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 46 Maths Textbook Solution.

Answers (1)

Answer: $\frac{-\pi}{10}$

Hint: Let’s start with cos function and solve $\sin ^{-1}$ function.

Given: $\sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)$

Solution:

$\sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)=\sin ^{-1}\left\{\cos \left(6 \pi+\frac{3 \pi}{5}\right)\right\}$

$=\sin ^{-1}\left\{\sin \left(\frac{\pi}{2}-\frac{3 \pi}{5}\right)\right\}$

$=\frac{\pi}{2}-\frac{3 \pi}{5}$

$=\frac{-\pi}{10}$

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 46 Maths Textbook Solution.

Answers (1)

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