Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • explain solution RD Sharma class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (ii) maths

explain solution RD Sharma class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (ii) maths

Answers (1)

Answer:   -\frac{\pi }{7}

Hint:  The range of principal value of \tan ^{-1} is \left [-\frac{\pi }{2} ,\frac{\pi }{2}\right ]
Given: \tan ^{-1}\left(\tan \frac{6 \pi}{7}\right)

Explanation:

First we solve \tan \frac{6\pi }{7}

            \begin{aligned} &\tan \frac{6 \pi}{7}=\tan \left(\pi-\frac{\pi}{7}\right) \\ &\tan \left(\pi-\frac{\pi}{7}\right)=-\tan \frac{\pi}{7}\; \; \; \; \; \; \; \; \; \quad(\tan (\pi-\theta)=-\tan \theta) \end{aligned}

We know 

            \tan ^{-1}(\tan x)=x \text { if } x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

            \tan ^{-1}\left(\tan \frac{6 \pi}{7}\right)=-\frac{\pi}{7}

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question