Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter 3 Inverse Trigonometric Functions exercise  Very short answer question 27 math

Need solution for RD Sharma maths class 12 chapter 3 Inverse Trigonometric Functions exercise  Very short answer question 27 math

Answers (1)

Answer:-\frac{\pi}{4}

Given: \tan ^{-1}\left\{\tan \left(\frac{15 \pi}{4}\right)\right\}

Hint: Try to solve the \tan  function first.

\therefore \tan (4 \pi-x)=-\tan x

Solution:      

\begin{aligned} \tan ^{-1}\left\{\tan \left(\frac{15 \pi}{4}\right)\right\} &=\tan ^{-1}\left\{\tan \left(4 \pi-\frac{\pi}{4}\right)\right\} \\ &=\tan ^{-1}\left\{\tan \left(\frac{\pi}{4}\right)\right\} \\ &=\tan ^{1}\left\{\tan \left(-\frac{\pi}{4}\right)\right\} \\ &=\frac{-\pi}{4} \end{aligned}

Posted by

infoexpert22

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date 2025 Live: CBSE, ICSE, BSEB, MPBSE Class 10, 12 timetable out; Punjab, Rajasthan schedule soon
anam-khan

CBSE Board Exams 2025: Guidelines issued for Class 10, 12 practicals
anam-khan

Board Exam Date Sheet 2025 Live: ICSE, ISC, CBSE, MP time table out; BSEB routine soon

Latest Question