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Name: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 13 maths textbook solution
Uploaded: Thu, 2021-08-05 22:37
Description: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 13 maths textbook solution

#RD Sharma Vol. 1 Class 12
#School
#R.D. Sharma
#Inverse Trigonometric Functions
#Maths
#CBSE 12 Class

#1.3
#3.1
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 13 maths textbook solution

Answers (1)

Answer: $100 \degree$

Given:

$\cos ^{-1}\left(\cos 1540^{\circ}\right)$

Hint: Try to separate the degree into two parts.

Solution:

$\begin{aligned} \cos ^{-1}\left(\cos 1540^{\circ}\right) &=\cos ^{-1}\left\{\cos \left(1440^{\circ}+100^{\circ}\right)\right\} \\ &=\cos ^{-1}\left\{\cos \left(100^{\circ}\right)\right\} \quad \therefore\left[\cos \left(4 \pi+100^{\circ}\right)=\cos 100^{\circ}\right] \\ &=100^{\circ} \end{aligned}$

Posted by

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 13 maths textbook solution

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