Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.11 Question 3 Subquestion (ii) Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.11 Question 3 Subquestion (ii) Maths Textbook Solution.

Answers (1)

Answer:
x=\frac{1}{4},-8
Hint:
Here, we can use the below formula,
\tan^{-1}A+\tan^{-1}B=\tan^{-1}\left ( \frac{A+B}{1-AB} \right )
Given:
\tan^{-1}\left ( x+1 \right )+\tan^{-1}\left (x-1 \right )=\tan^{-1}\left (\frac{8}{31} \right )
Solution:
Here,     A=x+1
                B=x-1
So, let’s put the values of A and B in the formula of \tan^{-1}A+\tan^{-1}B
\! \! \! \! \! \! \! \! \! \Rightarrow \tan^{-1}\left (x+1 \right )+\tan^{-1}\left ( x-1\right ) = \tan^{-1}\left ( \frac{8}{31} \right )\\ \Rightarrow \tan^{-1}\left ( \frac{x+1+x-1}{1-\left (x+1 \right )\left ( x-1 \right )} \right )=\tan^{-1}\frac{8}{31}\\ \Rightarrow \tan^{-1}\left ( \frac{2x}{1-\left ( x^{2}-1 \right )} \right )=\tan^{-1}\frac{8}{31}\\ \Rightarrow \frac{2x}{1-x^{2}+1}=\frac{8}{31}\\ \Rightarrow 31x=8-4x^{2}
\! \! \! \! \! \! \! \! \! \Rightarrow 4x^{2}+31x-8=0\\ \Rightarrow 4x^{2}+32x-x-8=0\\ \Rightarrow 4x\left ( x+8 \right )-1\left ( x+8 \right )=0\\ \Rightarrow 4x-1=0 \: or \: x+8=0\\ \Rightarrow x=\frac{1}{4} \: or \: x=- 8\\ \Rightarrow x=\frac{1}{4},-8

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question