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Name: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 48 math
Uploaded: Sat, 2021-08-07 08:14
Description: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 48 math

#Inverse Trigonometric Functions
#R.D. Sharma
#Maths
#CBSE 12 Class
#School
#RD Sharma Vol. 1 Class 12

#1.3
#3.1
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#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 48 math

Answers (1)

Answer: $\frac{2 \pi}{3}$

Given: $\cos ^{-1}\left[\cos \left(4 \pi+\frac{2 \pi}{3}\right)\right]$

Hint: Try to solve $\cos \left(\frac{14 \pi}{3}\right)$ function.

Solution:

$\cos ^{-1}\left(\cos \frac{14 \pi}{3}\right)=\cos ^{-1}\left[\cos \left(4 \pi+\frac{2 \pi}{3}\right)\right]$

$\begin{array}{l} =\cos ^{-1}\left(\cos \frac{2 \pi}{3}\right) \\\\ =\frac{2 \pi}{3} \end{array}$

Posted by

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 48 math

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