Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • explain solution rd sharma class 12 chapter inverse trigonometric functions exercise 3.2 question 4 sub question (i) maths

explain solution rd sharma class 12 chapter inverse trigonometric functions exercise 3.2 question 4 sub question (i) maths

Answers (1)

Answer: \frac{5\pi }{6}

Hint: Any x x\in \left [ -1,1 \right ],\cos ^{-1}represents an angle in \left ( 0,\pi \right )

Given:    \cos ^{-1}\left ( \frac{-\sqrt{3}}{2} \right )

Solution:

\cos ^{-1}\left ( \frac{-\sqrt{3}}{2} \right ) is an angle in \left [ 0,\pi \right ]whose cosine is \left ( \frac{-\sqrt{3}}{2} \right )

                                =\pi -\frac{\pi }{6}

                                =\frac{6\pi-\pi }{6}

  \cos ^{-1}\left ( \frac{-\sqrt{3}}{2} \right ) = \frac{5\pi }{6}

         

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exams 2025: Guidelines issued for Class 10, 12 practicals
anam-khan

Board Exam Date Sheet 2025 Live: ICSE, ISC, CBSE, MP time table out; BSEB routine soon
anam-khan

Board exam dates 2025: CBSE, CISCE, UP, MP, Maharashtra, TN time table out; state-wise updates

Latest Question