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Name: need solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (v)
Uploaded: Sun, 2021-08-01 17:07
Description: need solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (v)

#Maths
#School
#CBSE 12 Class
#R.D. Sharma
#RD Sharma Vol. 1 Class 12
#Inverse Trigonometric Functions

#1.3
#3.1
#3.2
#3.3
#3.4
#3.5
#3.6
#3.7
#3.8
#3.9
#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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need solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (v)

Answers (1)

Answer: 1

Hint: The range of principal value of $\tan ^{-1}$ is $\left [ -\frac{\pi }{2} ,\frac{\pi }{2}\right ]$
Given: $\tan ^{-1}(\tan 1)$

Explanation:

As we know $\tan ^{-1}(\tan x)=x \text { if } x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$

By substituting this condition in given question

$\tan ^{-1}(\tan 1)=1$

Hence, $\tan ^{-1}(\tan 1)=1$

Posted by

infoexpert26

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need solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (v)

Answers (1)

Posted by

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