Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D. Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.21 Question 2 maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.21 Question 2 maths Textbook Solution.

Answers (1)

Answer:2 \sqrt{x^{2}+2 x-1}-\log \left|x+1+\sqrt{x^{2}+2 x-1}\right|+c

Given:\int \frac{2 x+1}{\sqrt{x^{2}+2 x-1}} d x

Hint: Simplify it and solve it

Solution: Let I=\int \frac{2 x+1}{\sqrt{x^{2}+2 x-1}} d x

                    I=\int \frac{2 x+2-1}{\sqrt{x^{2}+2 x-1}} d x

                   \begin{aligned} &I=\int \frac{2 x+2}{\sqrt{x^{2}+2 x-1}} d x-\int \frac{1}{\sqrt{x^{2}+2 x-1}} d x \\ &I=\int \frac{2 x+2}{\sqrt{x^{2}+2 x-1}} d x-\int \frac{1}{\sqrt{x^{2}+2 x+1-1-1}} d x \\ &I=\int \frac{2 x+2}{\sqrt{x^{2}+2 x-1}} d x-\int \frac{1}{\sqrt{(x+1)^{2}-2}} d x \end{aligned}

                  Let

                   x^{2}+2x-1=y

                    dx\left ( 2x+2 \right )=dy

                    I=\int \frac{d y}{\sqrt{y}}-\int \frac{1}{\sqrt{(x+1)^{2}-(\sqrt{2})^{2}}} d x

                    I=\frac{\sqrt{y}}{\frac{1}{2}}-\log \left|x+1+\sqrt{x^{2}+2 x-1}\right|+c

                    \begin{aligned} &{\left[\int \frac{d x}{\sqrt{x^{2}-a^{2}}}=\log \left|x+\sqrt{x^{2}-a^{2}}\right|+c\right]} \\ &I=2 \sqrt{x^{2}+2 x-1}-\log \left|x+1+\sqrt{x^{2}+2 x-1}\right|+c \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question