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Explain Solution R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise Revision Exercise  Question 92 Maths Textbook Solution.

Answers (1)

Answer:

x \log _{10} x-x+c

Hint: You must know about integration of logx.

Given:

\int \log _{10} x d x

Solution: 

\int \log x d x

   \int \log x \cdot 1 d x

x \log x-\int \frac{1}{x} \cdot x d x                           \left[\because \int 1=x, \int I .11 d x=I \int I I d x-\int \frac{d}{d x} I \int I I d x\right]

x \log _{10} x-x+c

 

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