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  • Need solution for RD Sharma Maths Class 12 Chapter 18 Indefiite Integrals Excercise Fill in the Blanks Question 18

Need solution for RD Sharma Maths Class 12 Chapter 18 Indefiite Integrals Excercise Fill in the Blanks Question 18

Answers (1)

best_answer

Answer:

\frac{1}{20}\left(x^{2}+6 x+10\right)^{10}+c

Hint:

Simplify it and integrate it.

Solution:

I=\int(x+3)\left(x^{2}+6 x+10\right)^{9} d x

Let x^{2}+6x+10 =y                 …(i)

\begin{aligned} &(2 x+6) d x=d y \\ &(x+3) d x=\frac{d y}{2} \end{aligned}

\begin{aligned} &\Rightarrow I=\frac{1}{2} \int y^{9} d y \\ &I=\frac{1}{2}\left(\frac{y^{10}}{10}\right)+c \\ &I=\frac{1}{20}\left(x^{2}+6 x+10\right)^{10}+c \end{aligned}

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