Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18. 8 question 40 maths

Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 40 maths

Answers (1)

Answer:

        \frac{1}{3}log\left | 2+3sin^{-1}x \right |+C

Hint:

        \frac{\mathrm{d} }{\mathrm{d} x} sin^{-1}x=\frac{1}{\sqrt{1-x^{2}}}

Given:

        \int \! \frac{1}{\sqrt{1-x^{2}}(2+3sin^{-1}x)}dx                    ......(1)

Explanation:

Let

        2+3sin^{-1}x=t

        \frac{3}{\sqrt{1-x^{2}}}dx=dt

        \frac{dx}{\sqrt{1-x^{2}}}=\frac{dt}{3}

Put in (1) we get

        \frac{1}{3}\int \! \frac{dt}{t}=\frac{1}{3}log\left | t \right |+C

                      =\frac{1}{3}log\left | 2+3sin^{-1}x \right |+C

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 answer scripts to be checked via on-screen marking from 2026: Board
anam-khan

CBSE Admit Card 2026 (OUT) LIVE: Class 10 and 12 theory exam hall ticket at parikshasangam.cbse.gov.in
anam-khan

CBSE Admit Card 2026 LIVE: How to download CBSE Class 10th, 12th hall ticket when out; exam dates, guidelines

Latest Question