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need solution for rd sharma maths class 12 chapter Indefinite integrals exercise 18.1 question 1 sub question (iv)

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Answer: \frac{-2}{\sqrt{x}}+c

Hint: You must know the integration of {x^{n}}

Given: \int \frac{1}{x^{\frac{3}{2}}}dx

Solution:\int \frac{1}{x^{\frac{3}{2}}}dx=\int x^{\frac{-3}{2}}dx

=\frac{x^{\frac{-3}{2}+1}}{\frac{-3}{2}+1}+c                    \left ( \because \int x^{n}dx=\frac{x^{n+1}}{n+1}+c \right )

=\frac{x^{\frac{-1}{2}}}{\frac{-1}{2}}+c=-2\times \frac{1}{\sqrt{x}}+c

= \frac{-2}{\sqrt{x}}+c

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