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Need solution for RD Sharma maths class 12 chapter Indefinite Integrals exercise 18.8 question 15

Answers (1)

Answer:

        log\left | log(tan\: x) \right |+C

Hint:

        tan\: x=\frac{sin\: x}{cos\: x},\: \: sec\: x=\frac{1}{cos\: x},\: \: cos\: ecx=\frac{1}{sin\: x}

Given:

        \int \! \frac{sec\: x\: cos\: ecx}{log\left ( tan\: x \right )}dx

Explanation:

Let

        log(tan\: x)=t

        \frac{1}{tan\: x}(sec^{2}x)dx=dt

        \Rightarrow \frac{sec\: x}{\frac{sin\: x}{cos\: x}}\times \frac{1}{cos\: x}dx=dt

        \Rightarrow sec\: x\: cos\: ecx\: dx=dt

        =\int \! \frac{dt}{t}\: \: \: =log\: t+C

        =log\left | log(tan\: x) \right |+C

Posted by

Gurleen Kaur

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