Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.21 Question 8 Maths Textbook Solution.

Please Solve R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.21 Question 8 Maths Textbook Solution.

Answers (1)

Answer:  \sqrt{x^{2}-1}+2 \log \left|x+\sqrt{x^{2}-1}\right|+c

Given: \int \frac{x+2}{\sqrt{x^{2}-1}} d x

Hint: Simplify the given function

Solution: I=\int \frac{x+2}{\sqrt{x^{2}-1}} d x

           \begin{aligned} &I=\frac{1}{2} \int \frac{2 x}{\sqrt{x^{2}-1}} d x+2 \int \frac{1}{\sqrt{x^{2}-1}} d x \\ &I=\frac{1}{2}\left[\frac{x^{2}-1}{\frac{1}{2}}\right]+2 \log \left|x+\sqrt{x^{2}-1}\right|+c \end{aligned}

           \left[\begin{array}{l} U \sin g \\ \int(f(x))^{n} f^{1}(x) d x=\frac{f(x)^{n+1}}{n+1}+c \\ \int \frac{1}{\sqrt{x^{2}-a^{2}}} d x=\log \left|x+\sqrt{x^{2}-a^{2}}\right|+c \end{array}\right]

           I=\sqrt{x^{2}-1}+2 \log \left|x+\sqrt{x^{2}-1}\right|+c

        

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th Result 2026 Date LIVE: Class 12 scores at cbse.gov.in soon; how to check, toppers list
anam-khan

CBSE 12th Result 2026 Date: Here’s what previous years’ trends indicate
anam-khan

CBSE Class 12th marks uploading for schools in West Asia starts from April 8

Latest Question