Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.3 Question 8 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise 18.3 Question 8 Maths Textbook Solution.

Answers (1)

Answer: \frac{2}{3(a-b)}\left\{(x+a)^{\frac{3}{2}}-(x+b)^{\frac{3}{2}}\right\}+c

Hint:\text { To solve this equation we add } \sqrt{x+a}-\sqrt{x+b} \text { to numerator and denominator }

Given: \int \frac{1}{\sqrt{x+a}+\sqrt{x+b}} d x

Solution: \int \frac{1}{\sqrt{x+a}+\sqrt{x+b}} d x

\text { Multiply } \sqrt{x+a}-\sqrt{x+b} \text { to numerator and denominator }

\begin{aligned} &\int \frac{\sqrt{x+a}-\sqrt{x+b}}{(\sqrt{x+a}+\sqrt{x+b})(\sqrt{x+a}-\sqrt{x+b})} d x \\ &=\int \frac{\sqrt{x+a}-\sqrt{x+b}}{(x+a)-(x+b)} d x \end{aligned}

\begin{aligned} &=\int \frac{\sqrt{x+a}-\sqrt{x+b}}{a-b} d x \\ &=\frac{1}{a-b} \int \sqrt{x+a}-\sqrt{x+b} d x\left[\int(x)^{n}=\frac{(x)^{n+1}}{n+1}+c\right] \\ &=\frac{1}{a-b}\left[\frac{(x+a)^{\frac{3}{2}}}{\frac{3}{2}}-\frac{(x+b)^{\frac{8}{2}}}{\frac{3}{2}}\right]+c \\ &=\frac{1}{a-b} \times \frac{2}{3}\left[(x+a)^{\frac{3}{2}}-(x+b)^{\frac{8}{2}}\right]+c \\ &=\frac{2}{3(a-b)}\left[(x+a)^{\frac{3}{2}}-(x+b)^{\frac{8}{2}}\right]+c \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question