Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need Solution for R.D. Sharma Maths Class 12 Chapter 18 Indefinite Integrals Exercise Revision Exercise Question 109 Maths Textbook Solution.

Need Solution for R.D. Sharma Maths Class 12 Chapter 18 Indefinite Integrals Exercise Revision Exercise Question 109 Maths Textbook Solution.

Answers (1)

Answer:\tan ^{-1} \sqrt{x}(1+x)-\sqrt{x}+c

Hint: to solve this equation we have to use Byparts method

Given:\int \tan ^{-1} \sqrt{x} d x

Solution: \text { let } \sqrt{x}=t

\frac{1}{2 \sqrt{x}} d x=d t

d x=2 t d t

I=\int \tan ^{-1} t .2 t d t

I=\tan ^{-1} t . t^{2}-\int \frac{t^{2}+1-1}{1+t^{2}} d t \ldots . \text { using Byparts }

I=\tan ^{-1} t \cdot t^{2}-\int d t+\int \frac{1}{1+t^{2}}

I=\tan ^{-1} t \cdot t^{2}-t+\tan ^{-1} t+C

I=\tan ^{-1} t\left(1+t^{2}\right)-t+C

I=\tan ^{-1} \sqrt{x}(1+x)-\sqrt{x}+C

 

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question