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Need solution for RD Sharma Maths Class 12 Chapter 18 Indefinite Integrals Excercise Very Short Answers Question 48

Answers (1)

Answer: \frac{x^{2}}{2}+\frac{1}{x}+c

Hints: You must know about the integral rule of functions

Given: \int \frac{x^{3}-1}{x^{2}}dx

Solutions: \int \frac{x^{3}-1}{x^{2}}dx

\int \frac{x^{3}}{x^{2}}+\frac{1}{x^{2}}dx

\begin{aligned} &\int\left(x-\frac{1}{x^{2}}\right) d x \\ &\int x d x-\int \frac{1}{x^{2}} d x \\ &\int x d x-\int x^{-2} d x \\ &{\left[\frac{x^{1+1}}{1+1}\right]-\left[\frac{x^{-2+1}}{-2+1}\right]+c} \\ &\frac{x^{2}}{2}-\frac{x^{-1}}{-1}+c \\ &\frac{x^{2}}{2}+\frac{1}{x}+c\quad\quad\quad\quad\quad\quad\left[\int x^{n} d x=\frac{x^{n+1}}{n+1}\right] \\ \end{aligned}

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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