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Please Solve R.D.Sharma Class 12 Chapter 18 Indefinite Integrals Exercise  Revision Exercise Question 31 Maths Textbbok Solution.

Answers (1)

Answer:

-\frac{1}{3} \cot ^{3} x+\cot x+x+c

Given:

\int \cot ^{4} x d x

Hint:

To solve the given statement split the given term \left(\cot ^{4} x\right) into \left(\cot ^{2} x \cot ^{2} x\right)

Solution: 

\int \cot ^{2} x\left(\operatorname{cosec}^{2} x-1\right) d x

    I=\int \cot ^{2} x \operatorname{cosec}^{2} x d x-\int \cot ^{2} d x                        

    I=\int \cot ^{2} x \operatorname{cosec}^{2} x d x-\int\left(\operatorname{cosec}^{2} x-1\right) d x                                \left[\because \cot x=p, \operatorname{cosec}^{2} x d x=-d p\right.

    I=-\int p^{2} d p+\int d p+\int d x

    I=-\frac{p^{8}}{3}+p+x+c

    I=-\frac{1}{3} \cot ^{3} x+\cot x+x+c

 

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