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Provide Solution For R.D.Sharma Maths Class 12 Chapter 18  Indefinite Integrals Exercise Multiple Choice Questions Question 23 Maths Textbook Solution.

Answers (1)

Answer:

\frac{1}{3} \tan ^{3} x+C

Given:

\int \frac{\sin ^{2} x}{\cos ^{4} x} d x

Hint:

You must know about the derivation of tan x and \int x^{n} d x

Explanation:

Let I=\int \frac{\sin ^{2} x}{\cos ^{4} x} d x

        =\int \tan ^{2} x \sec ^{2} x d x                                                            \left[\because \frac{\sin x}{\cos x}=\tan x ; \frac{1}{\cos x}=\sec x\right]

Put \tan x=t, \sec ^{2} x d x=d t

      \begin{aligned} &=\int t^{2} d t \\ &=\frac{(t)^{2+1}}{2+1}+C \\ &=\frac{1}{3} \tan ^{3} x+C \end{aligned}

Hence,\int \frac{\sin ^{2} x}{\cos ^{4} x}=\frac{1}{3} \tan ^{3} x+C .

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