Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • provide solution for RD Sharma maths class 12 chapter Indefinite Integrals exercise 18.26 question 2

provide solution for RD Sharma maths class 12 chapter Indefinite Integrals exercise 18.26 question 2

Answers (1)

best_answer

Answer:
The correct answer is \frac{e^{x}}{x^{2}}+c
Hint: using integration by parts, \int u . v d x=u \int v d x-\int\left[\int v d x \frac{d u}{d x} d x\right]

Given:

Solution:

        =\int e^{x}\left(\frac{1}{x^{2}}-\frac{2}{x^{3}}\right) d x

        =\int e^{x} \cdot \frac{1}{x^{2}} d x-2 \int \frac{e^{x}}{x^{3}} d x

        =\int e^{x} \cdot x^{-2} d x-2 \int \frac{e^{x}}{x^{8}} d x

        \begin{aligned} &=x^{-2} \int e^{x} d x-\int\left[\frac{d}{d x}\left(x^{-2}\right) \int e^{x} d x\right] d x-2 \int \frac{e^{x}}{x^{3}} d x+c \\ &=x^{-2} \cdot e^{x}-\int-2 x^{-3} e^{x} d x-2 \int \frac{e^{x}}{x^{3}} d x+c \\ &=x^{-2} \cdot e^{x}+c \end{aligned}

        =\frac{e^{x}}{x^{2}}+c

So, the correct answer is   \frac{e^{x}}{x^{2}}+c

 

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question