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Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 16 maths

Answers (1)

Answer:

        log\left | 3+log\: x \right |+C

Hint:

        \frac{\mathrm{d} }{\mathrm{d} x}(log\: x)=\frac{1}{x}

Given:

        \int \! \frac{1}{x(3+log\: x)}dx

Explanation:

Let

        (3+log\: x)=t

        \frac{1}{x}dx=dt

        =\int \! \frac{dt}{t}\: \: \: =log\: t+C

        =log\left | 3+log\: x \right |+C

Posted by

Gurleen Kaur

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