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Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 24 maths

Answers (1)

Answer:

        log\left | log\: sin\: x \right |+C

Hint:

        cot\: x=\frac{cos\: x}{sin\: x}

Given:

        \int\! \frac{cot\: x}{log\: sin\: x}dx                    ........(1)

Explanation:

Let

        log\: sin\: x=t

        \frac{1}{sin\: x}(cos\: x)dx=dt

        cot\: x\: dx=dt

Put in (1)

        \int\! \frac{dt}{t}=log\left | t \right |+C

        =log\left | log\: sin\: x \right |+C

Posted by

Gurleen Kaur

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