Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 4 maths

Explain solution RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 4 maths

Answers (1)

Answer:

        -2log\left | cos\frac{x}{2} \right |+C

Hint:

        cos \: 2\: x=2cos^{2}\: x-1=1-2sin^{2}\: x

Given:

        \int \sqrt{\frac{1-cos\: x}{1+cos\: x}}dx

Explanation:

       \int \sqrt{\frac{2sin^{2}\frac{x}{2}}{2cos^{2}\frac{x}{2}}}dx                    [cos\: x=2cos^{2}\: \frac{x}{2}-1\: \: or\; \; 1-2sin^{2}\frac{x}{2}]

    \int tan\frac{x}{2}dx

Let \frac{x}{2}=t

dx=2dt

2\int tan\: tdt=-2log\left | cos\: t \right |+C

                        =-2log\left | cos\: \frac{x}{2} \right |+C

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question