Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 9 maths textbook solution

Please solve RD Sharma class 12 chapter Indefinite Integrals exercise 18.8 question 9 maths textbook solution

Answers (1)

Answer:

        -log\left | cos\: x-sin\: x \right |+C

Hint:

        tan\: x=\frac{sin\: x}{cos\: x}

Given:

        \int \! \frac{1+tan\: x}{1-tan\: x}dx

Explanation:

        \int \! \frac{1+\frac{sin\: x}{cos\: x}}{1-\frac{sin\: x}{cos\: x}}dx=\int \! \frac{cos\: x+sin\: x}{cos\: x-sin\: x}dx

Let,

        cos\: x-sin\: x=t

        (-sin\: x-cos\: x)dx=dt

        =\int \! \frac{dt}{t}

        =-log\left | t \right |

        =-log\left | cos\: x-sin\: x \right |+C

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 10th, 12th results 2024 ‘shortly’; board issues Digilocker access code for students
anam-khan

CBSE Class 10, 12 results 2024 likely after May 20, says result portal
anam-khan

CBSE Result Date 2024 after May 20 at cbse.nic.in; Know Class 10th, 12th passing marks

Latest Question