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Please solve RD Sharma class 12 chapter Indefinite Integrals exercise 18.9 question 1 maths textbook solution

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 Solution: We have , 

       I=\int \frac{\log (\log x)}{x}dx

Put     \log x=t\Rightarrow \frac{1}{x}dx=dt

\\ \\ I=\int \log t dt=t[\log t-1]+c\\ \\ I=\log x[\log (\log x)-1]+c

                                           

 

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