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Provide Solution For  R.D.Sharma Maths Class 12 Chapter 18  Indefinite Integrals Exercise  Revision Exercise Question 93 Maths Textbook Solution.

Answers (1)

Answer:

(\log x) \cdot \log (\log x)-\log x+c

Hint:

You must know about integration of log.

Given:

\int \frac{\log (\log x)}{x} d x

Solution:

\operatorname{let} \log x=t

  \frac{d x}{x}=d t

\int \log (t) d t

t \log t-t+c                                    \int I . I I d x=I \int I I d x-\int \frac{d}{d x} I \int I 1 d x

 put value of t

(\log x) \cdot \log (\log x)-\log x+c

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