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Provide solution for RD Sharma maths class 12 chapter Indefinite Integrals exercise 18.8 question 18

Answers (1)

Answer:

        log\left | log\: x \right |+C

Hint:

        \frac{\mathrm{d} }{\mathrm{d} x}(log\: x)=\frac{1}{x}

Given:

        \int \! \frac{1}{x\: log\: x}dx

Explanation:

Let

        log\: x=t

        \frac{1}{x}dx=dt

                =\int \! \frac{dt}{t}

                =log\: t+C

                =log\left | log\: x \right |+C

Posted by

Gurleen Kaur

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