Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 22

Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.7 question 22

Answers (1)

Answer:

 \frac{3}{11}

Hint:

 Use Baye’s theorem.

Given:

 In certain college 4% of boy and 1% of girl are taller than 1.75 meter. Furthermore 60% of student in colleges are girl. A student selected at garden from college is found be taller 1.75 meter.

Solution:

Let E1 and E2  denote the selected student is a girl and selected student is a boy.

A denoted the student is 1.75m tall.

\begin{aligned} &P(E_1)=\frac{60}{100}\\ &P(E_2)=\frac{40}{100}\\ &P\left ( \frac{A}{E_1} \right )=\frac{1}{100}\\ &P\left ( \frac{A}{E_2} \right )=\frac{4}{100}\\ \end{aligned}

Using Baye’s theorem we get

\begin{aligned} &P\left (\frac{E_1}{A} \right )=\frac{P(E_1).P\left ( \frac{A}{E_1} \right )}{P(E_1)\times P\left ( \frac{A}{E_1} \right )+P(E_2)\times P\left ( \frac{A}{E_2} \right )}\\ &=\frac{{\frac{60}{100}\times \frac{1}{100} }}{\frac{60}{100}\times \frac{1}{100}+\frac{40}{100}\times \frac{4}{100}}\\ &=\frac{6}{6+16}\\ &=\frac{6}{22}\\ &=\frac{3}{11} \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question