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  • Provide solution for RD sharma maths class 12 chapter 30 Probablity Exercise very short answer question, question 8

Provide solution for RD sharma maths class 12 chapter 30 Probablity Exercise very short answer question, question 6

Answers (1)

The required probability is \frac{16}{81}

Hint:

Probability \; of \;an \;event = \frac{Total\; number\; of \; favorable\; outcome}{Total\; number\; of\; sample\; space}

Given:

A die is rolled four times

Explanation:

When a die is rolled ,

S = Total No. of outcomes

   = {1,2,3,4,5,6}

n(S) = 6

Let A be an event of getting not less than 2 & not greater than 5.
⇒ A={2,3,4,5}

n(A)=4

\Rightarrow P(A)=\frac{n(A)}{n(S)}=\frac{4}{6}

Since a die is rolled four times so, the probability in getting four throws

=\left (\frac{4}{6} \right ) \times \left (\frac{4}{6} \right ) \times \left (\frac{4}{6} \right ) \times \left (\frac{4}{6} \right )\\ =\frac{16}{81}

Thus, the required probability is  = \frac{16}{81}

 

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