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  • Provide Solution For R.D. Sharma Maths Class 12 Chapter 30 Probaility Exercise Multiple Choice Questions Question 26 Maths Textbook Solution.

Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise Multiple Choice Questions Question 26 Maths Textbook Solution.

Answers (1)

Answer: a

Hint: You must know the rules of finding probability.

Given: 100 cards numbered 1 to 100 one card is drawn at random

Solution: Number divisible by 6 between 1 to 100 =16

Number divisible by 8 between 1 to 100 = 12

Number divisible by 6 and 8 between 1 to 100 = 4

Number divisible by 24 between 1 to 100 = 4                      

\begin{aligned} &P(6 \cup 8)=P(6)+P(8)-P(6 \cap 8) \\ &=\frac{16}{100}+\frac{12}{100}-\frac{4}{100} \\ &=\frac{24}{100} \\ &=\frac{6}{25} \end{aligned}

P(Number divisible by 6 or 8 but not by 24) = P(divisible by 6 or 8) – P(divisible by 24)

\begin{aligned} &\frac{6}{25}-\frac{4}{100} \\ \end{aligned}

\begin{aligned} &=\frac{5}{25}=\frac{1}{5} \end{aligned}       

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