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  • Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability Exercise 30.4 Question 16 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.4 Question 16 Maths Textbook Solution.

Answers (1)

Answer: 0.8645

Given: An article manufactured by a company consists of two parts X and Y. In the process of manufacture of the part X, 9 out of 100 parts may be defective. Similarly, 5 out of 100 are likely to be defective in the manufacture of part Y.

Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Solution:

Let, A= Particle X is defective

      B= Particle Y is defective

            P\left ( A \right )=\frac{9}{100}

            P\left ( B \right )=\frac{5}{100}

Required Probability =P\left ( \bar{A}\cap \bar{B} \right )

                               \begin{aligned} &=\mathrm{P}(\overline{\mathrm{A}}) \times \mathrm{P}(\overline{\mathrm{B}}) \\ &=[1-\mathrm{P}(\mathrm{A})][1-\mathrm{P}(\mathrm{B})] \\ &=\left[1-\frac{9}{100}\right]\left[1-\frac{5}{100}\right] \\ &=\frac{91}{100} \times \frac{95}{100} \\ &=0.8645 \end{aligned}

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