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  • Explain Solution R.D.Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 22 Sub Question 1 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 22 Sub Question 1 Maths Textbook Solution.

Answers (1)

Answer: \frac{16}{121}

Hint:  Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 1) 2 red balls

Solution:           

                    Total\: balls = 4 red+7 black=11 balls

                    \begin{aligned} \mathrm{P}(2 \text { red balls }) &=\mathrm{P}(\text { first ball is red }) \times \mathrm{P}(\text { second ball is red }) \\ &\left.=\frac{4}{11} \times \frac{4}{11} \ldots \text { as replacement is allowed }\right\} \\ &=\frac{16}{121} \end{aligned}

                       
                                         

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