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Please solve RD Sharma class 12 chapter Probability exercise 30.2 question 11 maths textbook solution

Answers (1)

Answer:

 \frac{3}{7}

Hint:

\begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given, events

            A=A black ball in the 1st draw

            B=A black ball in the 2nd draw

Now,

\begin{aligned} &P(A)=\frac{10}{15}=\frac{2}{3}\\ &P\left ( \frac{B}{A} \right )=\frac{9}{14}\\ &\text { Required Probability }=P(A\cap B)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\\ &=\frac{2}{3}\times \frac{9}{14}\\ &=\frac{3}{7} \end{aligned}

Posted by

Gurleen Kaur

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