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Please Solve R.D. Sharma class 12 Chapter 30 Probability  Exercise Multiple Choice Questions Question 11 Maths Textbook Solution.

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Answer: c

Hint: You must know the rules of finding probability.

Given:Out of 30 consecutive integers, 2 are chosen at random

Solution: for sum of two integers to be odd, one integer should be even and other should be odd

In 30 consecutive integers, 15 are even and 15 are odd

P(sum is odd) = P(first odd, second even) + P(first even, second odd)

\begin{aligned} &\Rightarrow\left(\frac{15}{30} \times \frac{15}{29}\right)+\left(\frac{15}{30} \times \frac{15}{29}\right) \\ &\Rightarrow \frac{450}{30 \times 29} \\ &\Rightarrow \frac{15}{29} \end{aligned}

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