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  • Please Solve R.D. Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 9 Maths Textbook Solution.

Please Solve R.D. Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 9 Maths Textbook Solution.

Answers (1)

Answer:\frac{1}{2}

Hint: You must know the rules of finding probability

Given:

Probability \: \: of \: \: Arun's \: \: selection=\frac{1}{4}=P\left ( A \right )
Probability \: \: of \: \: Tarun's \: \: rejection=\frac{2}{3}=P\left ( \bar{B} \right )
Solution:

\begin{aligned} &P(\text { Arun's selected })=\frac{1}{4} \\ &P(\text { Tarun's rejected })=\frac{2}{3} \\ &P(\text { Tarun's selected })=\frac{1}{1}-\frac{2}{3}=\frac{1}{3} \end{aligned}

\begin{aligned} &\mathrm{P}(\text { atleast one of them gets selected })=P(A \cup B) \\\\ &P(A \cup B)=P(A)+P(B)-P(A \cap B) \\\\ &=P(A)+P(B)-P(A) P(B) \\ \end{aligned}

\begin{aligned} &=\frac{1}{4}+\frac{1}{3}-\frac{1}{4} \times \frac{1}{3} \\ &=\frac{1}{4}+\frac{1}{3}-\frac{1}{12} \\ &=\frac{3+4-1}{12}=\frac{6}{12} \\ &=\frac{1}{2} \end{aligned}

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