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Need Solution for R.D. Sharma Maths Class 12 Chapter 30 Probability Exercise Multiple Choice Questions Question 48 Maths Textbook Solution.

Answers (1)

Answer:(d)

Hint: You must know the rules of finding probability.

Given: 3 persons A,B,C

\begin{aligned} &P(A)=0.4 \\ &P(B)=0.3 \\ &P(C)=0.2 \end{aligned}

Solution:P(A)=0.4, P(B)=0.3, P(C)=0.2

\begin{aligned} &P(\bar{A})=1-P(A)=1-0.4=0.6 \\ &P(\bar{B})=1-P(B)=1-0.3=0.7 \\ &P(\bar{C})=1-P(C)=1-0.2=0.8 \end{aligned}

Now,

\mathrm{P}_{(\text {twohits })}=P(A \cap \bar{B} \cap C)+P(A \cap B \cap \bar{C})+P(\bar{A} \cap B \cap C)

\begin{aligned} &=P(A) P(\bar{B}) P(C)+P(A) P(B) P(\bar{C})+P(\bar{A}) P(B) P(C) \\ &=(0.4 \times 0.3 \times 0.8)+(0.4 \times 0.7 \times 0.2)+(0.6 \times 0.3 \times 0.2) \\ &=0.096+0.056+0.036 \\ &=0.188 \end{aligned}

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