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  • Explain Solution R.D. Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 23 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 23 Maths Textbook Solution.

Answers (1)

Answer:\frac{26}{49}

Hint:probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: The probabilities of two students A and B coming to the school in time are

             \frac{3}{7} &\frac{5}{7}

Solution:

As we know, Two events are said to be independent if the product of the events are equal to their intersection. i.e.P\left ( A\cap B \right )=P\left ( A \right )P\left ( B \right )

                \begin{aligned} &P(A \text { coming in time })=\frac{3}{7} \\ &P(\text { A not coming in time })=1-\frac{3}{7}=\frac{4}{7} \\ &P(B \text { coming in time })=\frac{5}{7} \\ &P(B \text { not coming in time })=1-\frac{5}{7}=\frac{2}{7} \\ \end{aligned}

                \begin{aligned} &P(\text { only one of } A \& B \text { comin } g \text { in time })=P(A) P(\bar{B})+P(\bar{A}) P(B) \\ \end{aligned}

                                                                                               \begin{aligned} &=\frac{3}{7} \times \frac{2}{7}+\frac{4}{7} \times \frac{5}{7} \\ &=\frac{26}{49} \end{aligned}

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