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Need Solution for R.D.Sharma Maths Class 12 Chapter 30 Probability  Exercise 30.4 Question 13 Maths Textbook Solution.

Answers (1)

Answer: \frac{1}{3}

Hint: Use  P\left ( A\cap B \right )=P\left ( A \right )P\left ( B \right )

Given:

             A = No. 4, 5 or 6 on first toss

             B = 1, 2, 3 or 4 on second toss

Solution:

\mathrm{S}=\left\{\begin{array}{l} (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), \\ (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\ (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\ (4,1),(4,2),(4,3),(4,4),(4,5),(4,6) \\ (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\ (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) \end{array}\right\}

               n\left ( S \right )=36

           \begin{aligned} &P(A)=\frac{18}{36}=\frac{1}{2} \\ &P(B)=\frac{24}{36}=\frac{2}{3} \\ &\begin{aligned} P(A \cap B) &=P(A) P(B) \\ &=\frac{1}{2} \times \frac{2}{3} \\ &=\frac{1}{3} \end{aligned} \end{aligned}

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