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Need solution for RD Sharma maths class 12 chapter Probability exercise 30.1 question 7

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Answer:

\begin{aligned} &0.2, \frac{2}{3} \end{aligned}

Hint:

Just simplify to find P (A|B)

Given, P(A) =  0.4

       P(B)  =   0.3

Now

\begin{aligned} &P(A\mid B)=\frac{n(A\cap B)}{ n(A)}\\ &0.5=\frac{n(A\cap B)}{ 0.4 }\\ &P(A\cap B)=0.20 \end{aligned}

Therefore,

\begin{aligned} &P(A\mid B)=\frac{n(A\cap B)}{ n(B)}\\ &=\frac{0.2}{ 0.3 }\\ &=\frac{2}{3} \end{aligned}

Posted by

Gurleen Kaur

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