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Please solve RD Sharma class 12 chapter Probability exercise 30.1 question 9 maths textbook solution

Answers (1)

Answer:

 \frac{1}{3},\frac{1}{2}

Hint:

Use Formula

\text { Probability }=\frac{\text { No. of event happened }}{ \text { Total no. of events }}

Given, conditions

Let, the whole possibility

S = { (M1M2), (M1F2), (F1F2), (F1M2) }

Let ,  A      =  Both child are female

                 =  (F1F2)

       B        = Elder child is female

                 = { (F1M2), (F1F2) }

   C         =  At Least one child is a male

               =  { (M1F1), (F1M2), (M1M2) }

   D         =   Both children are male

              =  (M1M2)

D ∩ C       =   (M1M2)

A ∩ B       =  (F1F2)

  1. Required probability

P(D\mid C)=\frac{n(D\cap C)}{ n(C)}=\frac{\frac{1}{4}}{\frac{3}{4}}=\frac{1}{3}

2. Required probability

P(A\mid B)=\frac{\frac{1}{4}}{\frac{2}{4}}=\frac{1}{2}

Posted by

Gurleen Kaur

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