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Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 12

Answers (1)

Answer:

 \begin{aligned} &\frac{2}{5525} \end{aligned}

Hint:

\begin{aligned} &\text { Probability }=P(A\cap B\cap C)=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right ) \end{aligned}

Given, events

            A=A king in the 1st draw

            B=A king in the 2nd draw

\begin{aligned} &P(A)=\frac{4}{52}=\frac{1}{13}\\ &P\left ( \frac{B}{A} \right )=\frac{3}{51}=\frac{1}{17}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{4}{50}=\frac{2}{25}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right )\\ &=\frac{1}{13}\times \frac{1}{17}\times \frac{2}{25}\\ &=\frac{2}{5525} \end{aligned}

Posted by

Gurleen Kaur

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