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Please Solve R.D.Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 6 Sub Question 2 Maths Textbook Solution.

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Answer:\frac{8}{15}

Hint: You must know the rules of finding probability

Given:Probability of Kamal’s selection=\frac{1}{3}

Probability of Monika’s selection=\frac{1}{5}

Solution:P( Kamal selected)=\frac{1}{3}=P\left ( A \right )

P( Monika selected)=\frac{1}{5}=P\left ( B \right )

\begin{aligned} &\mathrm{P}(\text { none of them get selected })=P(\bar{A}) \times P(\bar{B}) \\ &=[1-P(A)][1-P(B)] \\ &=\left(1-\frac{1}{3}\right) \times\left(1-\frac{1}{5}\right) \\ &=\frac{2}{3} \times \frac{4}{5} \\ &=\frac{8}{15} \end{aligned}

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