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  • Please solve RD Sharma class 12 chapter Probability exercise 30.2 question 1 maths textbook solution

Please solve RD Sharma class 12 chapter Probability exercise 30.2 question 1 maths textbook solution

Answers (1)

Answer:

 \frac{1}{221}

Hint:

Use formula of probability, where

P(A\cap B)=P(A)\times P\left ( \frac{B}{A} \right )

Given,  a pack of 52 cards.

Solution: So Let, A = A king in first trial

               B = A king in second trial.

Now, Total cards are 52.

\begin{aligned} &P(A)=\frac{ \text { No. of elements of A }}{\text { Total no. of elements }}\\ &=\frac{4}{52}=\frac{1}{13} \end{aligned}

Now

\begin{aligned} &P\left ( \frac{B}{A} \right )=\text { A consecutive king without replacement after first trial.}\\ &=\frac{\text { No. of kings in cards }}{\text { Total number of cards after excluding one king }}\\ &=\frac{3}{51} \qquad \text { (After trail cards will be and there will be kings) }\\ &=\frac{1}{17} \end{aligned}

Now,

\begin{aligned} &\text { Required Probability }=P(A\cap B)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\\ &=\frac{1}{13}\times \frac{1}{17}\\ &=\frac{1}{221} \end{aligned}

Posted by

Gurleen Kaur

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