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  • Please Solve R.D. Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 6 Sub Question 4 Maths Textbook Solution.

Please Solve R.D. Sharma class 12 Chapter 30 Probaility  Exercise 30.5 Question 6 Sub Question 4 Maths Textbook Solution.

Answers (1)

Answer:\frac{2}{5}

Hint: You must know the rules of finding probability

Given:Probability of Kamal’s selection=\frac{1}{3}

Probability of Monika’s selection=\frac{1}{5}

Solution:P( Kamal selected)=\frac{1}{3}=P\left ( A \right )

P( Monika selected)=\frac{1}{5}=P\left ( B \right )

\begin{aligned} &\mathrm{P} \text { (one of them gets selected) }=P(\bar{A}) P(B)+P(\bar{B}) P(A) \\\\ &{\left[\begin{array}{l} P(\bar{A}) \text { means A is not selected } \\\\ P(\bar{B}) \text { means B is not selected } \end{array}\right]} \\\\ &=P(B)[1-P(A)]+P(A)[1-P(B)] \\ \end{aligned}

\begin{aligned} &=\frac{1}{5}\left(1-\frac{1}{3}\right)+\frac{1}{3}\left(1-\frac{1}{5}\right) \\ &=\frac{2}{15}+\frac{4}{15} \\ &=\frac{6}{15} \\ &=\frac{2}{5} \end{aligned}

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