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  • Provide Solution For R. D. Sharma Maths Class 12 Chapter 30 Probaility Exercise Multiple Choice Questions Question 23 Maths Textbook Solution.

Provide Solution For R. D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise Multiple Choice Questions Question 23 Maths Textbook Solution.

Answers (1)

Answer:(c)

Hint: You must know the rules of finding probability.

Given: Bag X = (2W + 3B) balls

Bag Y = (4W + 2B) balls

One bag is selected at random and one ball is drawn.

Solution:

\begin{aligned} &\mathrm{E}_{1}=\text { Selecting bag } \mathrm{X} \\ &\mathrm{E}_{2}=\text { Selecting bag } \mathrm{Y} \\ &\mathrm{A}=\text { Drawing white ball } \end{aligned}

\begin{aligned} &\therefore P\left(\mathrm{E}_{1}\right)=\frac{1}{2} \\ &P\left(\mathrm{E}_{2}\right)=\frac{1}{2} \\ &P\left(\frac{A}{\mathrm{E}_{1}}\right)=\frac{2}{5} \\ &P\left(\frac{A}{\mathrm{E}_{2}}\right)=\frac{4}{6}=\frac{2}{3} \end{aligned}

Using the law of total probability,

Required problem \begin{aligned} &=P(A)=P\left(E_{1}\right) P\left(\frac{A}{E_{1}}\right)+P\left(E_{2}\right) P\left(\frac{A}{E_{2}}\right) \\ \end{aligned}

\begin{aligned} &=\left(\frac{1}{2} \times \frac{2}{5}\right)+\left(\frac{1}{2} \times \frac{2}{5}\right) \\ &=\frac{1}{5}+\frac{1}{3} \\ &=\frac{8}{15} \end{aligned}

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