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  • Need solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 13

Need solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 13

Answers (1)

Answer:

 \begin{aligned} &\frac{44}{91} \end{aligned}

Hint:

\begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given,

            A=A good orange in the 1st draw

            B=A good orange in the 2nd draw

            C=A good orange in the 3rd draw

Now,

\begin{aligned} &P(A)=\frac{12}{15}=\frac{4}{5}\\ &P\left ( \frac{B}{A} \right )=\frac{11}{14}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{10}{13}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right )\\ &=\frac{4}{5}\times \frac{11}{14}\times \frac{10}{13}\\ &=\frac{440}{910}=\frac{44}{91} \end{aligned}

Posted by

Gurleen Kaur

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