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  • Explain Solution R.D. Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 22 Sub Question 3 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 22 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer: \frac{56}{121}

Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 1) one red and one black ball

Total\: \: balls = 4 red+7 black=11 balls

           P\left ( One\: red\: \&\: One Black \right )

                                            \begin{aligned} &=P(\text { first red and second black })+P(\text { first black and second } \mathrm{red}) \\ &=\frac{4}{11} \times \frac{7}{11}+\frac{4}{11} \times \frac{7}{11} \\ &=\frac{56}{121} \end{aligned}

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