Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D. Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 22 Sub Question 3 Maths Textbook Solution.

Explain Solution R.D. Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 22 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer: \frac{56}{121}

Hint: Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 1) one red and one black ball

Total\: \: balls = 4 red+7 black=11 balls

           P\left ( One\: red\: \&\: One Black \right )

                                            \begin{aligned} &=P(\text { first red and second black })+P(\text { first black and second } \mathrm{red}) \\ &=\frac{4}{11} \times \frac{7}{11}+\frac{4}{11} \times \frac{7}{11} \\ &=\frac{56}{121} \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question