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  • Provide Solution For R.D. Sharma Maths Class 12 Chapter 30 Probaility Exercise Multiple Choice Questions Question 25 Maths Textbook Solution.

Provide Solution For  R.D. Sharma Maths Class 12 Chapter 30 Probaility  Exercise Multiple Choice Questions Question 25 Maths Textbook Solution.

Answers (1)

Answer:  d

Hint: You must know the rules of finding probability.

Given: Year of 22nd century chosen at random, there will be 53 Sundays

Solution: P(53 Sunday in a leap year)=\frac{2}{7}

P(53 Sunday in a non-leap year)=\frac{1}{7}

There will be 24 leap years in 22nd century from 2201 to 2200,

P (leap year)=\frac{24}{100}

P (non-leap year)=\frac{76}{100}

Now,

P (53 Sundays) = P (leap year)\timesP(Sundays in a leap year) +P (non-leap year)\times (53 Sundays)

\begin{aligned} &\Rightarrow \frac{24}{100} \times \frac{2}{7}+\frac{76}{100} \times \frac{1}{7} \\ &\Rightarrow \frac{48}{700}+\frac{76}{700} \\ &\Rightarrow \frac{124}{700} \\ &\Rightarrow \frac{31}{175} \end{aligned}

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